Math homework? help!?

Marita Stadick: a million) four.nine + four/17 = four.ninety + zero.23 = five.thirteen two) a million/two + a million/two = two/two = a million three) four/nine + a million/three = four/nine + three/nine = 7/nine = zero.seventy seven four) a million/two - four/17 = nine/34 17/34 - eight/34 = nine/34 nine/34 = nine/34 ==> CORRECT five) five/6 - five/17 = zero.eighty three - zero.29 = zero.fifty four 6) a million/two - three/eleven = five.five/eleven - three/eleven = two.five/eleven = zero.227 7) five/7 - three/thirteen = zero.seventy one - zero.23 = zero.forty eight eight) a million/two x three/thirteen = three/26 (a million x three) / (two x thirteen) = three/26 three / 26 = three/26 ==> CORRECT nine) a million/two x four/eleven = (a million x four) / (two x eleven) = four / 22 = two/eleven 10) four/7 x five/19 = (four x five) / (7 x 19) = 20 / forty five = four/nine eleven) a million/two x five/12 = (a million x five) / (two x 12) = five / 24 12) five/eight / (five/thirt! een) = a million five/eight five/eight x thirteen/five = a million + five/eight (five x thirteen) / (eight x five) = eight/eight + five/eight sixty five / forty = thirteen/eight thirteen / eight = thirteen/eight ==> CORRECT thirteen) five/7 / (two/7) = five/7 x 7/two = (five x 7) / (7 x two) = 35 / 14 14) two/three / (a million/four) = two/three x four = eight / three 15) a million/two / (two/nine) = a million/two x nine/two = nine / (two x two) = nine / four In a few instances, while we have now a fragment it's greater if we write it as a decimal (with ease via dividing the numerator with the denominator). But in a few instances additionally it is a greater thought to paintings most effective with the numerators of the fractions (if they have got the identical denominator). Also, keep in mind that after dividing fractions you're honestly multiplying the fraction via the reciprocal of the opposite one. Example: two/nine divided via five/eight ==> two/nine / (five/eight) div! ided (/) via five/eight ==> instances (x) eight/five (reciproc! al of five/eight) two/nine / (five/eight) = two/nine x eight/five = (two x eight) / (nine x five) = sixteen / forty five NOTE: If the fraction will also be simplified, do it. In this example sixteen and forty five can not be simplified however they are able to be awarded as a decimal (sixteen/forty five = zero.35). Hope this helped and well good fortune! :)...Show more

Clemente Schoeck: 1)Let f(x) = px^3 - 2x^2 + qx + 3 , where p and q are constants. When the f(x) is divided by (2x+1) , the remainder is -1 . When the f(x) is divided by (2x+1) the remainder is 3.Find the value of p and q.When divided by 2x - 1x = 1/2p/8 - 1/2 + q/2 + 3 = -1, according to remainder theoremWhen divided by 2x + 1x = -1/2p/8 - 1/2 + q/2 + 3 = 3This doesn't work..check your question2)The remainder is 8 when the polynomial x^2 + ax + b is divided by (x-2) . The remainder is 9 when another polynomial x^2 - bx + a is divided by (x + 2 ) .Find the values of a and b.When x^2 + ax + b is divided ! by (x-2), x = 2Sub into x^2 + ax + b4 + 2a + b = 8 by remainder theorem ...................................(1)When x^2 - bx + a is divided by (x+2), x = -2Sub into x^2 - bx + a4 - (-2b) + a = 94 + a + 2b = 98 + 2a + 4b = 18 .................................(2)Solve simultaneously:(2) - (1) =4 + 3b = 103b = 6b = 2Sub into (1)4 + 2a + 2 = 82a = 2a = 1Done!P.S. if you can, clarify the first question, and I will help you solve it....Show more